A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When switched off, it

Question

A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When switched off, it rotates through 46.0 revolutions before coming to rest. Assuming it is constant, what is the magnitude of angular acceleration (in rad/s2)?

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Thạch Thảo 4 years 2021-07-19T23:51:58+00:00 1 Answers 13 views 0

Answers ( )

  1. giabao
    0
    2021-07-19T23:53:08+00:00
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    Answer:

    The magnitude of angular acceleration is 232.38\ rad/s^2.

    Explanation:

    Given that,

    Initial angular velocity, \omega_i=3500\ rev/min=366.5\ rad/s

    When it switched off, it comes o rest, \omega_f=0

    Number of revolution, \theta=46=289.02\ rad

    We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :

    \omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{-(366.51)^2}{2\times 289.02}\\\\\alpha =-232.38\ rad/s^2  

    So, the magnitude of angular acceleration is 232.38\ rad/s^2. Hence, this is the required solution.

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