A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times before coming

Question

A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times before coming to rest. Find the constant angular acceleration of the centrifuge (in rad/s2). Consider the direction of the initial angular velocity to be the positive direction, and include the appropriate sign in your result.

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Minh Khuê 7 months 2021-07-14T07:10:19+00:00 1 Answers 4 views 0

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    2021-07-14T07:11:49+00:00

    Answer:

    Explanation:

    Given,

    initial angular speed, ω = 3,700 rev/min

                                          = 3700\times \dfrac{2\pi}{60}=387.27\ rad/s

    final angular speed = 0 rad/s

    Number of time it rotates= 46 times

    angular displacement, θ = 2π x 46 = 92 π

    Angular acceleration

    \alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}

    \alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}

    \alpha = -259.28 rad/s^2

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