A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk? July 17, 2021 by Hưng Khoa A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk?
Answer: First of all the formula is F= uR,( force= static friction× reaction) mass= 5+25=30 F= 50 R= mg(30×10)=300 u= ? F=UR u= F/R u= 50/300=0.17N Reply
Answer:
First of all the formula is F= uR,( force= static friction× reaction)
mass= 5+25=30
F= 50
R= mg(30×10)=300
u= ?
F=UR
u= F/R
u= 50/300=0.17N