A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk?

Question

A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk?

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Hưng Khoa 6 months 2021-07-17T06:55:10+00:00 1 Answers 16 views 0

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    2021-07-17T06:56:16+00:00

    Answer:

    First of all the formula is F= uR,( force= static friction× reaction)

    mass= 5+25=30

    F= 50

    R= mg(30×10)=300

    u= ?

    F=UR

    u= F/R

    u= 50/300=0.17N

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