a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5 bills was 10

Question

a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5 bills was 10 more than 4 times the amount of $10 bills. the register contained as many $1 bills as $5 bills and $10 bills combined, and two $50 bills. how many bills of each kind did the register contain?

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Kiệt Gia 6 months 2021-08-10T01:34:03+00:00 2 Answers 4 views 0

Answers ( )

    0
    2021-08-10T01:35:06+00:00

    85 ones

    70 fives

    15 tens

    2 fifties

    0
    2021-08-10T01:35:54+00:00

    9514 1404 393

    Answer:

    • 85 ones
    • 70 fives
    • 15 tens
    • 2 fifties

    Step-by-step explanation:

    Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us …

      a +5b +10c +50d = 685 . . . . . total amount of cash

      b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

      a = b+c . . . . . . . . . . . as many ones as fives and tens combined

      d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

    __

    Substituting for ‘a’, then for ‘b’, we have …

      (b+c) +5b +10c +50d = 685

      6(10 +4c) +11c +50d = 685

      60 +35c +50d = 685

    Substituting d=2 and subtracting 160 gives …

      35c = 525

      c = 15

      b = 10 +4c = 10 +4(15) = 70

      a = b+c = 70 +15 = 85

    The register contained …

    • 85 ones
    • 70 fives
    • 15 tens
    • 2 fifties

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