Question

a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of$5 bills was 10 more than 4 times the amount of $10 bills. the register contained as many$1 bills as $5 bills and$10 bills combined, and two $50 bills. how many bills of each kind did the register contain? in progress 0 6 months 2021-08-10T01:34:03+00:00 2 Answers 4 views 0 Answers ( ) 1. 85 ones 70 fives 15 tens 2 fifties 2. 9514 1404 393 Answer: • 85 ones • 70 fives • 15 tens • 2 fifties Step-by-step explanation: Let a, b, c, d represent the numbers of$1, $5,$10, and \$50 bills, respectively. The problem statement tells us …

a +5b +10c +50d = 685 . . . . . total amount of cash

b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

a = b+c . . . . . . . . . . . as many ones as fives and tens combined

d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

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Substituting for ‘a’, then for ‘b’, we have …

(b+c) +5b +10c +50d = 685

6(10 +4c) +11c +50d = 685

60 +35c +50d = 685

Substituting d=2 and subtracting 160 gives …

35c = 525

c = 15

b = 10 +4c = 10 +4(15) = 70

a = b+c = 70 +15 = 85

The register contained …

• 85 ones
• 70 fives
• 15 tens
• 2 fifties