A car was traveling at a velocity of 8 m/s and then accelerated at a rate of 5 m/sr^2, reaching a velocity of 85 m/s. How far did the car tr

Question

A car was traveling at a velocity of 8 m/s and then accelerated at a rate of 5 m/sr^2, reaching a velocity of 85 m/s. How far did the car travel at this acceleration rate?

in progress 0
Thạch Thảo 4 years 2021-07-14T04:54:13+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-14T04:56:00+00:00

    Answer:

    716.1 m

    Explanation:

    A car was travelling at a velocity of 8m/s

    It accelerated at 5m/s^2

    It finally reached a velocity of 85m/s

    The distance can be calculated by applying the fourth equation of motion

    V^2= U^2 +2as

    V= 85m/s

    U= 8m/s

    a= 5m/s^2

    85^2= 8^2 + 2(5)(s)

    7225= 64 + 10s

    7225-64= 10s

    7161=10s

    s= 7161/10

    = 716.1 m

    Hence the car travelled at a distance of 716.1 m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )