A car takes 12 s to go from v=0m/s to v = 20 m/s at constant acceleration. Part A If you wish to find the distance traveled using the equati

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A car takes 12 s to go from v=0m/s to v = 20 m/s at constant acceleration. Part A If you wish to find the distance traveled using the equation d=1/2at2, what value should you use for a?

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Delwyn 2 months 2021-07-30T19:49:12+00:00 1 Answers 6 views 0

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    2021-07-30T19:51:11+00:00

    Answer:

    a = 1.67 m/s²

    Explanation:

    Given that,

    Initial speed, u = 0

    Final speed, v = 20 m/s

    Time, t = 12 s

    We need to find the distance traveled using the equation, d = 1/2 at².

    Where

    a is acceleration, a = (v-u)/t,

    a=\dfrac{20-0}{12}=1.67\ m/s^2

    So,

    d=\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\d=\dfrac{1}{2}\times {v-u}\times t\\\\d=\dfrac{1}{2}\times {20-0}\times 12\\\\d=10\ m

    Hence, the acceleration is 1.67 m/s² and the distance traveled is 10m.

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