A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m. What was its acceleration?

Question

A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m. What was its acceleration?

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Orla Orla 16 hours 2021-07-21T22:27:02+00:00 1 Answers 0 views 0

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    2021-07-21T22:28:27+00:00

    Answer:

    Acceleration, a=3.08\ m/s^2      

    Explanation:

    We have,

    Initial speed of the car, u = -27.7 m/s

    Final speed, v = -10.9 m/s

    Displacement, d = -105 m

    It is required to find acceleration of the car. Acceleration of an object is equal to the change in velocity divided by time.

    The relation between displacement, velocity and acceleration is given by third equation of motion.

    v^2-u^2=2ad

    a is acceleration

    a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(-10.9)^2-(-27.7)^2}{2(-105)}\\\\a=3.08\ m/s^2

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