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A car moves in a straight line such that for a short time it’s velocity is defined by V = (9t+ 2t) m/s, where t is in second
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Answers ( )
Answer:
s = 90 m
a = 56 m/s²
Explanation:
I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t
Position is the integral of differential velocities
s =
s = 3t³ + t² | from 0 to 3
s = 3(3)³ + 3² – (0) = 90 m
acceleration is the derivative of velocity
a = v’ = 18t + 2
a(3) = 18(3) + 2 = 56 m/s²