A car moves in a straight line such that for a short time it’s velocity is defined by V = (9t+ 2t) m/s, where t is in second

Question

A car moves in a straight line such that for a
short time it’s velocity is defined by V = (9t+ 2t) m/s, where t
is in seconds. Determine its position and acceleration when t = 3s.
When t = 0, S=0​

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Thu Hương 3 years 2021-08-31T00:19:07+00:00 1 Answers 205 views 0

Answers ( )

    0
    2021-08-31T00:21:05+00:00

    Answer:

    s = 90 m

    a = 56 m/s²

    Explanation:

    I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t

    Position is the integral of differential velocities

    s = \int\limits^3_0 {9t^2 + 2t} \, dt

    s = 3t³ + t² | from 0 to 3

    s = 3(3)³ + 3² – (0) = 90 m

    acceleration is the derivative of velocity

    a = v’ = 18t + 2

    a(3) = 18(3) + 2 = 56 m/s²

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