A car is traveling at 20.0 m/s on tires with a diameter of 70.0 cm. The car slows down to a rest after traveling 300.0 m. If the tires rolle

Question

A car is traveling at 20.0 m/s on tires with a diameter of 70.0 cm. The car slows down to a rest after traveling 300.0 m. If the tires rolled without slipping, what was the magnitude of the average angular acceleration of the tires during the time the car slowed to a rest

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Diễm Kiều 1 month 2021-08-08T17:55:43+00:00 1 Answers 1 views 0

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    2021-08-08T17:56:58+00:00

    Answer: deceleration of 1.904\ rad/s^2

    Explanation:

    Given

    Car is traveling at a speed of u=20 m/s

    The diameter of the car is d=70 cm

    It slows down to rest in 300 m

    If the car rolls without slipping, then it must be experiencing pure rolling i.e. a=\alpha \cdot r

    Using the equation of motion

    v^2-u^2=2as\\

    Insert v=0,u=20,s=300

    0-(20)^2=2\times a\times 300\\\\a=\dfrac{-400}{600}\\\\a=-\dfrac{2}{3}\ m/s^2

    Write acceleration as a=\alpha \cdot r

    -\dfrac{2}{3}=\alpha \times 0.35\\\\\alpha =-\dfrac{2}{1.05}\\\\\alpha =-1.904\ rad/s^2

    So, the car must be experiencing the deceleration of 1.904\ rad/s^2.

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