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## A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instead to an 18 V

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A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instead to an 18 V battery? A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instead to an 18 V battery? 2Q 4Q Q Q/2 Request Answer Part B – Potential difference in a parallel-plate capacitor

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Physics
5 months
2021-08-09T06:59:09+00:00
2021-08-09T06:59:09+00:00 2 Answers
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## Answers ( )

Answer:Part A:

Part B:

Explanation:The capacitance is given by:

Where:

So:

In the first case:

And in the second case:

or:

C is a constant so:

Therefore:

Part B:

To find thepotential difference in a parallel-plate capacitor just isolate from the capacitance equation:

Answer:2QExplanation:The expression for the electric charge stored in a capacitor is given as,

Q = CV………………… Equation 1

Where Q = Electric charge, C = Capacitance of the capacitor, V = Potential difference applied across the plates of the capacitor.

make C the subject of the equation

C = Q/V…………… Equation 2

Given: Q = Q, V = 9 V

Substitute into equation 2

C = Q/9 F.

If it is connected to an 18 V battery instead,

Q = CV

Given: C = Q/9 F, V = 18 V

Q = (Q/9)(18)

Q = 2Q.

Hence the charge on the capacitor = 2Q.