A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material that fills t

Question

A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material that fills the volume between the plates has a dielectric constant of 5.00. The plates of the capacitor are connected to a 400 V battery.

What is the capacitance of the capacitor?

What is the charge on either plate?

How much energy is stored in the charged capacitor?

in progress 0
Mộc Miên 4 years 2021-07-27T02:34:22+00:00 1 Answers 10 views 0

Answers ( )

  1. Amity
    0
    2021-07-27T02:36:00+00:00
    Reply

    Answer:

    Explanation:

    Area of plate

    A = 17cm² = 0.00017m²

    Separation distance

    d = 0.15cm = 0.0015m

    Dielectric material k = 5

    The plate of the capacitor are connected to

    Voltage =400V

    a. Capacitance of the capacitor?

    Capacitance of the capacitor can be determine by

    C = kεA/d

    ε = 8.854 × 10^-12F/m

    C=5×8.854×10^-12×0.00017/0.0015

    C = 5.017 × 10^-12 F

    C = 5.017 pF.

    The capacitance of the capacitor is 5.017 picoFarad

    b. The charge on a capacitor is given as

    q = CV

    q = 5.017 ×10^-12 × 400

    q = 2.007 × 10^-9

    q = 2.007 nC

    Each plate has a charge of 2.007nC but one is positive and the other is negative

    Q1 = +2.007nC

    Q2 = – 2.007nC

    So the charge on each plate is ±2.007 nano Coulombs

    c. Energy stored in a capacitor is given as

    E = ½CV²

    E = ½ × 5.017×10^-12 × 400²

    E = 4.0136 ×10^-7 J

    So the energy stored by the capacitor is 4.0136 × 10^-7 J.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )