# A canon is tilled back 30.0 degrees and shoots a cannon ball at 155 m/s. What is the highest point that the cannon ball reaches?

Question

A canon is tilled back 30.0 degrees and shoots a cannon ball at 155 m/s. What is the

highest point that the cannon ball reaches?

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1 year 2021-09-03T04:26:48+00:00 1 Answers 0 views 0

$$= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m$$

Therefore, highest point that the cannon ball reaches is 168.7m

Explanation:

the cannon is fired at an angle 30 o to the horizonatal with a speed of 155 m/s

highest point that the cannon ball reaches?

$$H_{max}=\frac{V^2\sin ^2 \theta}{2g}$$

g = 9.8m/s2

$$= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m$$

Therefore, highest point that the cannon ball reaches is 168.7m