(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.0 g. Silver has 47 electrons per atom

Question

(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.

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Ngọc Khuê 1 week 2021-07-22T01:33:29+00:00 1 Answers 0 views 0

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    2021-07-22T01:34:33+00:00

    Answer: The number of electrons in given amount of silver are 1.839\times 10^{24}

    Explanation:

    The number of moles is defined as the ratio of the mass of a substance to its molar mass.

    The equation used is:

    ……(1)

    We are given:

    Mass of silver = 7.0 g

    Molar mass of silver = 107.87 g/mol

    Putting values in equation 1:

    \text{Moles of silver}=\frac{7.0g}{107.87g/mol}=0.0650 mol

    According to the mole concept:

    1 mole of a compound contains 6.022\times 10^{23} number of particles.

    Number of electrons per atom of silver = 47

    So, 0.065 moles of silver will contain = (0.065\times 6.022\times 10^{23}\times 47)=1.839\times 10^{24} number of electrons

    Hence, the number of electrons in given amount of silver are 1.839\times 10^{24}

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