A cafeteria serving line has a coffee urn from which customers serve themselves Arrivals at the urn follow a Poisson distribution at the rat

Question

A cafeteria serving line has a coffee urn from which customers serve themselves Arrivals at the urn follow a Poisson distribution at the rate of three per minute. Customer service times are exponentially distributed with a mean of 15 seconds.

a) How many customers on average would you expect to see at the coffee station?

b) How long would you expect it to take to get a cup of coffee?

c) What percentage of time is the urn being used?

d) What is the probability that there are three or more people at the coffee station?

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Vodka 3 years 2021-08-25T09:25:07+00:00 1 Answers 201 views 0

Answers ( )

  1. kiet
    0
    2021-08-25T09:26:39+00:00
    Reply

    Answer:

    3 ; 1 minute ;75%

    Step-by-step explanation:

    Given :

    Service time = 15 seconds = 15/60 = 0.25 minute per customer

    μ = number of customers per minute = 1/0.25 = 4

    Arrival rate, λ= 3 persons per minute

    L = λ ÷ (μ – λ)

    L = 3 ÷ (4 – 3)

    L = 3 ÷ 1

    L = 3

    b) How long would you expect it to take to get a cup of coffee?

    L / arrival rate (λ)

    3 / 3

    = 1 minute

    c) What percentage of time is the urn being used?

    Utilization rate = λ/ μ

    = 3 / 4

    = 0.75 = 0.75 * 100% = 75%

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