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## A cable with a linear density of \mu=0.109~\text{kg/m}μ=0.109 kg/m is hung from telephone poles. The tension in the cable is 572 N. The dist

Question

A cable with a linear density of \mu=0.109~\text{kg/m}μ=0.109 kg/m is hung from telephone poles. The tension in the cable is 572 N. The distance between poles is 19.9 meters. The wind blows across the line, causing the cable resonate. A standing waves pattern is produced that has 4.5 wavelengths between the two poles. Assuming room temperature air, what is the frequency of the hum?

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Physics
6 months
2021-07-30T00:18:47+00:00
2021-07-30T00:18:47+00:00 1 Answers
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## Answers ( )

Answer:Explanation:The equation of the speed of a mechanical wave in terms of the tension and linear density, of the cable in our case, is given by:

Where:

And we know that

v = λ*fBecause a standing waves pattern is produced that has 4.5 wavelengths between the two poles and the distance between poles is 19.9 meters, the value of the wavelength is:

λ = 19.9/4.5 = 4.4 m.Therefore, the frequency will be:

I hope it helps you!