A bus started from Kathmandu and reached khanikhola,26km far from Kathmandu, in one hour. if the bus had uniform acceleration, calculate the

Question

A bus started from Kathmandu and reached khanikhola,26km far from Kathmandu, in one hour. if the bus had uniform acceleration, calculate the final velocity of the bus and acceleration. ​

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Kim Cúc 5 months 2021-08-04T12:54:55+00:00 1 Answers 75 views 0

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    2021-08-04T12:56:14+00:00

    Answer:

    a = 0.0040 m/s², v = 14.4 m/s.

    Step-by-step explanation:

    Given that,

    The distance between Kathmandu and Khanikhola, d = 26 km = 26000 m

    Time, t = 1 hour = 3600 seconds

    Let a is the acceleration of the bus. Using second equation of motion,

    d=ut+\dfrac{1}{2}at^2

    Where

    u is the initial speed of the bus, u = 0

    So,

    d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 26000}{(3600)^2}\\\\a=0.0040\ m/s^2

    Now using first equation of motion.

    Final velocity, v = u +at

    So,

    v = 0+0.0040(3600)

    v = 14.4 m/s

    Hence, this is the required solution.

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