A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the highest point, a

Question

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the highest point, as a wave passes. If the ripples decreaseto 4.7 cm, by what factor does thebug’s maximum KE change?

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Calantha 1 year 2021-08-09T00:14:14+00:00 1 Answers 13 views 0

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    2021-08-09T00:16:09+00:00

    Answer:

    factor that bug maximum KE change is 0.52284

    Explanation:

    given data

    vertical distance = 6.5 cm

    ripples decrease to =  4.7 cm

    solution

    We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

    KE = (0.5) × m × A² × ω²     ……………..1

    and kinetic energy is  directly proportional to square of the amplitude.

    so

    [tex]\frac{KE2}{KE1} = \frac{A2^2}{A1^2}[/tex]      ………….2

    [tex]\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}[/tex]

    [tex]\frac{KE2}{KE1}[/tex] = 0.52284

    so factor that bug maximum KE change is 0.52284

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