A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the highest point, a

Question

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the highest point, as a wave passes. If the ripples decreaseto 4.7 cm, by what factor does thebug’s maximum KE change?

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1 year 2021-08-09T00:14:14+00:00 1 Answers 13 views 0

factor that bug maximum KE change is 0.52284

Explanation:

given data

vertical distance = 6.5 cm

ripples decrease to =  4.7 cm

solution

We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

KE = (0.5) × m × A² × ω²     ……………..1

and kinetic energy is  directly proportional to square of the amplitude.

so

$$\frac{KE2}{KE1} = \frac{A2^2}{A1^2}$$      ………….2

$$\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}$$

$$\frac{KE2}{KE1}$$ = 0.52284

so factor that bug maximum KE change is 0.52284