## A buffer solution contains 0.475 M nitrous acid and 0.302 M sodium nitrite . If 0.0224 moles of potassium hydroxide are added to 150 mL of t

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## Answers ( )

Answer:The pH of the resulting solution will be 3.001Explanation:Molarity is calculated by using the equation:……(1)

We are given:Moles of NaOH = 0.0224 moles

Molarity of nitrous acid = 0.475 M

Molarity of sodium nitrite = 0.302 M

Volume of solution = 150 mL = 0.150 L

(Conversion factor: 1 L = 1000 mL)Putting values in equation 1, we get:The chemical equation for the reaction of nitrous acid and NaOH follows:I: 0.07125 0.0224 0.0453

C: -0.0224 -0.0224 +0.0224

E: 0.04885 – 0.0677

The power of the acid dissociation constant is the negative logarithm of the acid dissociation constant.

The equation used is:……(2)

We know:for nitrous acid =

Using equation 2:To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:…….(3)

Given values:Putting values in equation 3. we get:Hence, the pH of the resulting solution will be 3.001