A buffer is prepared containing 0.75 M NH3 and 0.20 M NH4 . Calculate the pH of the buffer using the Kb for NH3. g

Question

A buffer is prepared containing 0.75 M NH3 and 0.20 M NH4 . Calculate the pH of the buffer using the Kb for NH3. g

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Orla Orla 4 years 2021-07-12T09:12:45+00:00 1 Answers 8 views 0

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  1. Euphemia
    0
    2021-07-12T09:14:26+00:00
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    Answer:

    pH=8.676

    Explanation:

    Given:

    0.75 M NH_{3}

    0.20 M NH_{4}

    The objective is to calculate the pH of the buffer using the kb for NH_3

    Formula used:

    pOH=pka+log\frac{[salt]}{[base]}\\

    pH=14-pOH

    Solution:

    On substituting salt=0.75 and base=0.20 in the formula

    pOH=-log(1.77*10^{-5})+log\frac{0.75}{0.20}\\ =4.75+0.5740\\ =5.324

    pH=14-pOH

    On substituting the pOH value in the above expression,

    pH=14-5.324

    Therefore,

    pH=8.676

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