A boy and a girl are riding a merry- go-round which is turning ata constant rate. The boy is near the outer edge, while a girl is closer to

Question

A boy and a girl are riding a merry- go-round which is turning ata constant rate. The boy is near the outer edge, while a girl is closer to the center. Who has the greater tangential acceleration? 1. the boy 2. the girl 3. both have zero tangential 25% try penalty acceleration Hints: 0,0 4. both have the same non-zero tangential acceleration

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Linh Đan 1 year 2021-09-01T19:31:08+00:00 1 Answers 13 views 0

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    2021-09-01T19:32:53+00:00

    Answer:

    The correct answer is

    1. the boy 2.

    Explanation:

    Since Tangential acceleration = v²/r  then the

    v = ωr and v² =  ω²r² then the tangential acceleration = ω²r²/r = ω²r

    This shows that  since ω is the same for both of them, the boy with greater r has the most acceleration.

    The tangential acceleration [tex]a_t =[/tex] α·r

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )