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A boy and a girl are riding a merry- go-round which is turning ata constant rate. The boy is near the outer edge, while a girl is closer to
Question
A boy and a girl are riding a merry- go-round which is turning ata constant rate. The boy is near the outer edge, while a girl is closer to the center. Who has the greater tangential acceleration? 1. the boy 2. the girl 3. both have zero tangential 25% try penalty acceleration Hints: 0,0 4. both have the same non-zero tangential acceleration
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2021-09-01T19:31:08+00:00
2021-09-01T19:31:08+00:00 1 Answers
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Answer:
The correct answer is
1. the boy 2.
Explanation:
Since Tangential acceleration = v²/r then the
v = ωr and v² = ω²r² then the tangential acceleration = ω²r²/r = ω²r
This shows that since ω is the same for both of them, the boy with greater r has the most acceleration.
The tangential acceleration [tex]a_t =[/tex] α·r