A bowl contains 4 tangerines and 5 clementines. John randomly selects one piece of fruit, and then Pam randomly selects one of the

Question

A bowl contains 4 tangerines and 5 clementines. John randomly selects one piece of fruit, and then Pam randomly selects one of the remaining pieces of fruit. What is the probability that John selects a tangerine and Pam selects a clementine? Show all work and this is a independent/dependent question.

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Thu Giang 3 weeks 2023-01-08T16:37:11+00:00 1 Answer 0 views 0

Answer ( 1 )

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    2023-01-08T16:38:38+00:00
    Answer:
    5/18
    Step-by-step explanation:
    There are 9 pieces of fruit in the bowl,  tangerines and 5 clementines.
    Assuming that they do not put the fruit back
    P (tangerine) = number of tangerines/ total = 4/9
    Then John keeps his and there are  8 pieces of fruit in the bowl,  
    3 tangerines and 5 clementines.
    P (Clementine) = number of clementines/ total = 5/8
    P (tangerine, no replacement, Clementine) = P (tangerine) * P (Clementine)
                                                                           = 4/9 * 5/8 =5/18

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