A body of mass 2 kg moves in a (counterclockwise) circular path of radius 3 meters, making one revolution every 5 seconds. You may assume th

Question

A body of mass 2 kg moves in a (counterclockwise) circular path of radius 3 meters, making one revolution every 5 seconds. You may assume the circle is in the xy-plane, and so you may ignore the third component.
A. Compute the centripetal force acting on the body.
B. Compute the magnitude of that force.

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bonexptip 2 months 2021-07-24T01:13:59+00:00 1 Answers 5 views 0

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    2021-07-24T01:15:56+00:00

    Answer:

    a) \vec{F_{c}}=mR\omega^{2}

    \vec{F_{c}}=9.53 \: N \vec{r}

    b) |\vec{F_{c}}|=9.53 \: N

    Step-by-step explanation:

    a) The centripetal force equation is:

    \vec{F_{c}}=m\vec{a_{c}}

    \vec{F_{c}}=mR\omega^{2}

    Now, we know that the body makes one revolution every 5 seconds, so we can find the angular velocity:

    \omega=\frac{1 rev}{5 s}=0.2\: \frac{rev}{s}=1.26\: \frac{rad}{s}

    \vec{F_{c}}=2*3*1.26^{2}=9.53 \: N \vec{r}

    The centripetal force is a vector in the radius direction.

    b) The magnitude of that force will be:

    |\vec{F_{c}}|=9.53 \: N

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