A body moves with constant acceleration. It’s velocity increases from 6 m/s to 16 m/s in 2 seconds. The distance moved by the body in these

Question

A body moves with constant acceleration. It’s velocity increases from 6 m/s to 16 m/s in 2 seconds. The distance moved by the body in these 2 seconds is

in progress 0
Mộc Miên 5 months 2021-09-01T03:36:57+00:00 1 Answers 5 views 0

Answers ( )

    0
    2021-09-01T03:38:30+00:00

    Answer:

    The distance moved by the body in these 2 seconds is 22 meters.

    Explanation:

    Given that,

    Initial velocity of a body, u = 6 m/s

    Final velocity of the body, v = 16 m/s

    Time, t = 2 s

    Let d is the distance moved by the body in these 2 seconds is. Using third equation of motion to find it such that,

    v^2-u^2=2ad\\\\(16)^2-(6)^2=2\times (\dfrac{16-6}{2})\times d\\\\d = 22\ m

    So, the distance moved by the body in these 2 seconds is 22 meters. Hence, this is the required solution.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )