A body is projected from a point P with an initial speed of 30m/s, at an angle 65° to the horizontal. what is the vertical distance at the t

Question

A body is projected from a point P with an initial speed of 30m/s, at an angle 65° to the horizontal. what is the vertical distance at the time when the horizontal distance is 45 m?

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Ladonna 4 years 2021-08-27T23:18:53+00:00 1 Answers 36 views 0

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  1. Doris
    1
    2021-08-27T23:20:44+00:00
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    Answer:

    Vx = 30 * cos 65 = 12.7 m/s    initial horizontal speed

    Vy = 30 * sin 65 = 27.2 m/s    initial vertical speed

    t = 45 / 12.7 = 3.54 s     time to travel horizontal distance of 45 m

    h = vy t – 1/2 g t^2      height after time t

    h = 27.2 * 3.54 – 1/2 * 9.8 * 3.54^2 = 34.9 m

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