A body has an initial velocity of 12 m s^-1 and is brought to rest over a distance of 45 m. What is the acceleration of the body?

Question

A body has an initial velocity of 12 m s^-1 and is brought to rest over a distance of 45 m. What is the acceleration of the body?

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Xavia 6 months 2021-08-27T23:01:54+00:00 1 Answers 0 views 0

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    2021-08-27T23:03:42+00:00

    Answer:

    -1.46 m/s^2

    Explanation:

    Write down what is given first:

    v0 = 12 m/s

    vf = 0 m/s

    d = 45 m

    We are trying to find acceleration, so we will use the equation vf^2 = v0^2 + 2ad

    Plug in the values we have:

    0^2 = 12^2 + (2 x 45 x a)

    a = – 1.46 m/s^2

    Note that this acceleration is negative because the body is slowing down, so the acceleration with be negative, because the change in velocity is negative.

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