A box with a total surface area of 1.88 m^2
and
a wall thickness of 2.44 cm is made of an insulating material. A 14.1 W electric heater
inside the box maintains the inside temperature at 18.6
◦C above the outside temperature.
Find the thermal conductivity of the insulating material.
Answer in units of W/m ·
◦ C.
Answer:9.8×10^(-3) w/m°C
Explanation:
Quantity of heat(Q)=14.1w
Distance(d)=2.44cm=2.44/100=0.0244m
Area(a)=1.88m^2
Temperature change(t)=18.6°C
thermal conductivity(k)=?
K=(Qxd) ➗ (a x t)
K=(14.1×0.0244) ➗ (1.88×18.6)
K=0.34404 ➗ 34.968
K=9.8×10^(-3) w/m°C