A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 11 A, and that of the vacuum

Question

A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 11 A, and that of the vacuum cleaner is 4.0 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in one- half hour.

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Hưng Khoa 4 years 2021-08-13T12:50:55+00:00 1 Answers 217 views 0

Answers ( )

  1. thuhuong
    0
    2021-08-13T12:51:57+00:00
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    Answer:

    (a) P₁ = 1320 W

    (b) P₂ = 480 W

    (c) \frac{E_1}{E_2} = 0.46

    Explanation:

    (a)

    The power consumed by the blow dryer can be calculated as follows:

    P_1 = VI

    where,

    P₁ = Power Consumed by the blow dryer = ?

    V = Voltage = 120 V

    I = Current Rating of the blow dryer = 11 A

    Therefore,

    P_1 = (120\ V)(11\ A)\\

    P₁ = 1320 W

    (b)

    The power consumed by the blow dryer can be calculated as follows:

    P_2 = VI

    where,

    P₂ = Power Consumed by the vacuum cleaner = ?

    V = Voltage = 120 V

    I = Current Rating of the vacuum cleaner = 4 A

    Therefore,

    P_2 = (120\ V)(4\ A)\\

    P₂ = 480 W

    (c)

    \frac{E_1}{E_2} = \frac{P_1t_1}{P_2t_2}

    where,

    E₁ = Energy used by the blow-dryer

    E₂ = Energy used by the vacuum cleaner

    t₁ = time of use of the blow-dryer = (15 min)(60 s/1 min) = 900 s

    t₂ = time of use of the vacuum cleaner = (1.5 h)(3600 s/1 h) = 5400 s

    Therefore,

    \frac{E_1}{E_2} = \frac{(1320\ W)(900\ s)}{(480\ W)(5400\ s)}\\\\\frac{E_1}{E_2} = 0.46

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