A block of wood of mass 24 kg floats on water. The volume of the block below the surface of the water and the density of the wood.( Density

Question

A block of wood of mass 24 kg floats on water. The volume of the block below the surface of the water and the density of the wood.( Density of water= 1000kgm-3

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Hồng Cúc 3 years 2021-09-02T12:16:49+00:00 1 Answers 6 views 0

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  1. Dau
    0
    2021-09-02T12:18:35+00:00
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    Answer:

    0.024m^3

    Explanation:

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    Answer:

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    Given:-

    Mass of the block of wood = 24 kg

    Volume of wood = 0.032 m^3

    Density of water = 1000kg/m^3

    Now,

    Density of wood is given by,

    \frac{m}{v} = \frac{24}{0.032} \\

    \frac{m}{v} = 750 \: kg/m ^{3}

    Therefore,

    The density of wood is 750kg/m^3

    By principle of floatation,

    Mass \:of\: wood = Mass\: of\: liquid \:displaced

    Therefore,

    Mass of liquid displaced = 24kg

    Volume of liquid displaced (v),

    \frac{m}{v} = \frac{24}{1000} \\

    \frac{m}{v} = 0.24m ^{3}

    Now,

    Since the volume of the wood is equal to the volume of water displaced, it is 0.024m^3

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    Note:

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    => The volume of the wood below the water surface is the volume of water displaced.

    => Buoyant\: force = Weight\: of\: the \:displaced\: water.

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