## A block of mass m moving due east at speed v collides with and sticks to a block of mass 2m that is moving at the same speed vv but in a dir

Question

A block of mass m moving due east at speed v collides with and sticks to a block of mass 2m that is moving at the same speed vv but in a direction 45.0∘ north of east. Find the direction in which the two blocks move after the collision. Express your answer as an angle θ in degrees measured north of east.

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3 months 2021-07-19T22:37:19+00:00 1 Answers 4 views 0

30.36°

Explanation:

By using linear momentum; linear momentum can be expressed by the relation: where ;

m= mass = velocity of components in the x direction = velocity of components in the y direction

If we consider the east as the positive x and north as positive y which is synonymous to what we usually have on a graph.

Then;

Initial momentum = = However, the masses stick together after collision and move with a common velocity: ∴ Final momentum = = From the foregoing ;

initial momentum = final momentum So;   Finally;

The required angle θ = θ = θ = θ = 30.36°