A bike accelerates uniformly from rest to a speed of 8.59 m/s over a distance of 28.4m. Determine the acceleration of the bike.

Question

A bike accelerates uniformly from rest to a speed of 8.59 m/s over a distance of 28.4m. Determine the acceleration of the bike.

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Trúc Chi 5 months 2021-08-18T07:17:55+00:00 2 Answers 5 views 0

Answers ( )

    0
    2021-08-18T07:19:20+00:00

    Answer:

    1.3m/s²

    Explanation:

    Initial speed: vo=0m/s

    Final speed: vf=8.59m/s

    Distance: d=28.4m

    vf²=vo²+2×a×d (Galilei’s formula)

    a=(vf²-vo²)/2/d=8.59²/2/28.4=1.3m/s²

    0
    2021-08-18T07:19:21+00:00

    Answer:

    1.3m/s^2

    Explanation:

    Data obtained from the question include:

    U (initial velocity) = 0m/s

    V (final velocity) = 8.59 m/s

    s (distance) = 28.4m

    a (Acceleration) =?

    Using the equation of motion (v^2 = u^2 + 2as), the acceleration can be obtain as follows:

    v^2 = u^2 + 2as

    (8.59) ^2 = 0 + 2 x a x 28.4

    73.7881 = 56.8a

    Divide both side by the coefficient of a i.e 56.8

    a = 73.7881/56.8

    a = 1.3m/s^2

    Therefore, the acceleration of the bike is 1.3m/s^2

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