A bicycle wheel rotates at a constant 25 rev/min. What is true about its angular acceleration?

Question

A bicycle wheel rotates at a constant 25 rev/min. What is true about its angular acceleration?

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Neala 5 months 2021-08-14T15:30:32+00:00 1 Answers 11 views 0

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    2021-08-14T15:32:06+00:00

    Answer:

    The angular acceleration is zero

    Explanation:

    When an object is in rotational motion, it has a certain angular velocity, which is the rate of displacement of its angular position.

    This angular velocity can change or remain constant – this is given by the angular acceleration, which is:

    \alpha =\frac{\Delta \omega}{\Delta t}

    where

    \Delta \omega is the change in angular velocity

    \Delta t is the time elapsed

    Therefore, the angular acceleration is the rate of change of angular velocity.

    In this problem, the bicycle rotates at a constant angular velocity of

    \omega=25 rev/min

    This means that the change in angular velocity is zero:

    \Delta \omega=0

    And so, that the angular acceleration is zero:

    \alpha=0

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