A beam of protons is moving in the x direction with a speed of 10.6 km/s through a region in which the electric field is perpendicular to t

Question

A beam of protons is moving in the x direction with a speed of 10.6 km/s through a region in which the electric field is perpendicular to the magnetic field. The beam is not deflected in this region. If the magnetic field has a magnitude of 0.802 T and points in the y direction, find the magnitude and direction of the electric field. Give the x, y, and z component of the electric field.

in progress 0
RobertKer 1 week 2021-07-22T08:26:51+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-22T08:28:24+00:00

    Answer:

    E= 8501.2

    Explanation:

    Given Data;

    Speed = 10.6 km/s = 10.6*10^3 m/s

    Magnitude = 0.802 T

    The magnitude of the electric field is calculated using the formula;

    q E = q v B

    E = v B

       = 10.6 *10^3 * 0.802

       = 8501.2

    The direction of the electric field will point along the negative z-axis

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )