A beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 40° with the normal, and the re

Question

A beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 40° with the normal, and the refracted beam make an angle of 26° with the normal. What is the speed of light in the transparent material?

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Amity 1 day 2021-07-22T06:52:36+00:00 1 Answers 0 views 0

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    2021-07-22T06:53:53+00:00

    Answer:

    V = 2.05× 10⁸ m/s

    Explanation:

    We are given;

    The angle of the incidence; i = 40°

    Angle of refraction; (r) = 26°

    For us to find the speed of light in the material, we’ll use Snell’s law

    From shell’s law, we know that;

    n = sin i/sin r = speed of light in air/Speed of light in the medium

    Now, speed of light in air = 3 × 10⁸ m/s

    Lets speed of light in medium be V

    Thus, plugging in the relevant values to obtain;

    Sin 40°/sin 26° = 3×10⁸/V

    Let’s make V the subject;

    V = 3 × 10⁸× sin 26°/sin 40°

    V = 2.05× 10⁸ m/s

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