## A basketball is pressurized to a gauge pressure of PG 75 kPa when at the surface ofa swimming pool (Patm 101 kPa). The ball is then submerge

Question

A basketball is pressurized to a gauge pressure of PG 75 kPa when at the surface ofa swimming pool (Patm 101 kPa). The ball is then submerged in the pool of water which has a density p – 1000 kg/m. Assume the ball does not change in mass, Po or volume as it is submerged. Calculate the absolute pressure inside the basketball in kPa when it is at the surface.

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6 months 2021-07-29T02:28:57+00:00 2 Answers 50 views 0

P = 176 KPa

Explanation:

Given:-

– The gauge pressure of the basket-ball, PG = 75 KPa

Find:-

Calculate the absolute pressure inside the basketball in kPa when it is at the surface.

Solution:-

– The conversion of gauge pressure to absolute pressure is fairly simple.

– The gauge pressure of any object is pressure of the object relative to the atmospheric pressure ( Patm = 1 atm = 101 KPa.

– The conversion relation between gauge and atmospheric pressures is given:

P_abs = Patm + PG

– Use the given gauge pressure of the basketball PG = 75 KPa

P_abs = ( 101 + 75 ) KPa

P_abs = 176 KPa

– The absolute pressure of basketball at the surface of the water is P = 176 KPa