A baseball pitcher throws the ball in a motion where there is rotation of the forearm about the elbow joint as well as other movements. If t

Question

A baseball pitcher throws the ball in a motion where there is rotation of the forearm about the elbow joint as well as other movements. If the linear velocity of the ball relative to the elbow joint is 17.1 m/s at a distance of 0.470 m from the joint and the moment of inertia of the forearm is 0.500 kg·m^2. What is the rotational kinetic energy of the forearm?

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Diễm Thu 8 hours 2021-07-22T04:56:07+00:00 1 Answers 0 views 0

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    2021-07-22T04:57:52+00:00

    Answer: 330.88 J

    Explanation:

    Given

    Linear velocity of the ball, v = 17.1 m/s

    Distance from the joint, d = 0.47 m

    Moment of inertia, I = 0.5 kgm²

    The rotational kinetic energy, KE(rot) of an object is given by

    KE(rot) = 1/2Iw²

    Also, the angular velocity is given

    w = v/r

    Firstly, we calculate the angular velocity. Since it’s needed in calculating the Kinetic Energy

    w = v/r

    w = 17.1 / 0.47

    w = 36.38 rad/s

    Now, substituting the value of w, with the already given value of I in the equation, we have

    KE(rot) = 1/2Iw²

    KE(rot) = 1/2 * 0.5 * 36.38²

    KE(rot) = 0.25 * 1323.5

    KE(rot) = 330.88 J

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