A baseball is hit by a batter with an initial velocity of 95 miles per hour at 45° above the horizontal. The opposing team misses the catch

Question

A baseball is hit by a batter with an initial velocity of 95 miles per hour at 45° above the horizontal. The opposing team misses the catch and the baseball lands in the outfield 50 meters from where it started. How long was the baseball in the air

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Thiên Ân 5 months 2021-08-27T13:01:19+00:00 1 Answers 2 views 0

Answers ( )

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    2021-08-27T13:03:11+00:00

    Answer:

    5.61 seconds

    Explanation:

    The baseball moves as a projectile. Its angle is 45° and its velocity is 95 miles per hour.

    Let us convert this to metres per second:

    1 mile per hour = 0.45 m/s

    95 miles per hour = 95 * 0.45 = 42.75 m/s

    We need to find the time of flight of the baseball. Time of flight is given as:

    T = \frac{2u sin\alpha }{g}

    where u = initial velocity

    α = angle

    g = acceleration due to gravity (9.8 m/s)

    Therefore:

    T = \frac{2 * 42.75 * sin40}{9.8}\\ \\T = 5.61 secs

    The baseball was in the air for 5.61 seconds.

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