A balloon has an internal pressure of 1.95 atm and a volume of 5.0 L. If the temperature where the balloon is released is 20 °C, what

Question

A balloon has an internal pressure of 1.95 atm and a volume of 5.0 L. If the temperature where the balloon is
released is 20 °C, what will happen to the volume when the balloon rises to an altitude where the pressure is
0.65 atm and the temperature is -15 °C?

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Thu Giang 3 months 2021-08-02T18:22:46+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-08-02T18:24:00+00:00

    Answer:

    13.1 L

    Explanation:

    Using the combined gas law:

    P1V1/T1 = P2V2/T2

    Where;

    P1 = initial pressure (atm)

    P2 = final pressure (atm)

    V1 = initial volume (L)

    V2 = final volume (L)

    T1 = initial temperature (K)

    T2 = final temperature (K)

    Based on the information provided in this question;

    P1 = 1.95 atm

    P2 = 0.65 atm

    V1 = 5.0 L

    V2 = ?

    T1 = 20 °C = 20 + 273 = 293K

    T2 = -15 °C = -15 + 273 = 258K

    Using P1V1/T1 = P2V2/T2

    1.95 × 5/293 = 0.65 × V2/258

    9.75/293 = 0.65V2/258

    0.0333 = 0.00252V2

    V2 = 0.0333 ÷ 0.00252

    V2 = 13.1 L

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )