A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball’s acceleration?

Question

A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball’s acceleration?

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bonexptip 1 week 2021-07-21T05:23:53+00:00 1 Answers 2 views 0

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    2021-07-21T05:25:46+00:00

    Answer:

    -2.5m/s²

    Explanation:

    The acceleration of a body is giving by the rate of change of the body’s velocity. It is given by

    a = Δv / t        —————-(i)

    Where;

    a = acceleration (measured in m/s²)

    Δv = change in velocity = final velocity – initial velocity   (measure in m/s)

    t = time taken for the change (measured in seconds(s))

    From the question;

    i. initial velocity = 5m/s

    final velocity = 0 [since the body (ball) comes to rest]

    Δv = 0 – 5 = -5m/s

    ii. time taken = t = 2s

    Substitute these values into equation (i) as follows;

    a = (-5m/s) / (2s)

    a = -2.5m/s²

    Therefore, the acceleration of the ball is -2.5m/s²

    NB: The negative sign shows that the ball was actually decelerating.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )