A ball is thrown into the air with an upward velocity of 36 ft/s. It’s height h in feet after t seconds is given by the function h = -16t^2

Question

A ball is thrown into the air with an upward velocity of 36 ft/s. It’s height h in feet after t seconds is given by the function h = -16t^2 + 36t + 9. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the balls maximum height ?

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Kiệt Gia 6 months 2021-07-18T00:49:26+00:00 1 Answers 0 views 0

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    2021-07-18T00:50:34+00:00

    Answer:

    Time taken for the ball to hit the ground back = 3.08 s

    Step-by-step explanation:

    h(t)= -16t² + 48t + 4

    when will rhe object come back to hit rhe ground?

    When the ball is at the level.of the ground, h(t) = 0.

    0 = -16t² + 48t + 4

    -16t² + 48t + 4 = 0

    Solving the quadratic equation

    t = 3.08 s or t = -0.08 s

    Since the time cannot be negative,

    Time taken for the ball to hit the ground back = 3.08 s

    Hope this Helps!!!

    Step-by-step explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )