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## A ball is spun around in circular motion such that its frequency is 10 Hz. a. What is the period of its rotation? b. How much ti

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## Answers ( )

Answer:a = 0.1 s b. 10 s

Explanation:Given that,

The frequency in circular motion, f = 10 Hz

(a) Let T is the period of itsrotation. We know that,

T = 1/f

So,

T = 1/10

= 0.1 s

(b) Frequency is number of rotations per unit time. So,

Hence, this is the required solution.