A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light. B) De

Question

A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light.

B) Determine the power delivered to the same automobile light.

C) What potential difference is needed to produce a current of 5.0 mA through a 2.0 ? resistor?

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niczorrrr 18 hours 2021-07-22T04:00:14+00:00 1 Answers 0 views 0

Answers ( )

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    2021-07-22T04:01:21+00:00

    Answer:

    The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

    Explanation:

    Given:

    (A)

    Current I = 1 A

    Voltage V = 12 V

    For finding the resistance,

      V = IR

      R = \frac{V}{I}

      R = \frac{12}{1}

      R = 12Ω

    (B)

    For finding power delivered,

      P = I^{2} R

      P = (1) ^{2} \times 12

      P = 12 Watt

    (C)

    For finding the potential difference,

       V = IR

       V = 5 \times 10^{-3} \times 2

       V = 10 \times 10^{-3}

       V = 0.01 V

    Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )