A 927 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless track. The mass

Question

A 927 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless track. The mass is displaced 8 cm from the equilibrium point and released from rest. 5 N/m 927 g 8 cm x = 0 x Find the period of the motion. Answer in units of s.

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Maris 4 years 2021-09-01T03:59:28+00:00 2 Answers 10 views 0

Answers ( )

  1. Cherry
    0
    2021-09-01T04:00:36+00:00
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    Answer:

    2.7 s

    Explanation:

    The period of the motion of a massless loaded spring is given by

    T = 2\pi\sqrt{\dfrac{m}{k}}

    where m is the mass of the load and k is the force or spring constant.

    Using values in the question and converting to appropriate units,

    T = 2\pi\sqrt{\dfrac{927\times10^{-3}\text{ kg}}{5 \text{ N/m}}}= 2.7\text{ s}

  2. Nem
    0
    2021-09-01T04:00:42+00:00
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    Explanation:

    Below is an attachment containing the solution.

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