A + 8 μC charge lies 4 m to the left of a – 10 μC charge. A – 12 μC charge lies 8 m to its right. What is the resultant force on the center

Question

A + 8 μC charge lies 4 m to the left of a – 10 μC charge. A – 12 μC charge lies 8 m to its right. What is the resultant force on the center charge?

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Gerda 4 years 2021-07-30T14:07:59+00:00 1 Answers 8 views 0

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  1. thienthi
    0
    2021-07-30T14:09:27+00:00
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    Answer:

    both side charges will exert force on central charge towards left so the two forces add up. Thus resultant force on centre charge is

    F = 9×10^9 x 8×10^-6×10×10^-6/16

    +

    9× 10^9 × 10×10^-6×12×10^-6/64

    = 9× 10^9 × 10^ -12/16 (80+30)

    =6.18 × 10^-2 N

    or

    = 0.06 N

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