A 75.0 kg diver falls from rest into a swimming pool from a height of 5.10 m. It takes 1.34 s for the diver to stop after entering the water

Question

A 75.0 kg diver falls from rest into a swimming pool from a height of 5.10 m. It takes 1.34 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

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Adela 6 months 2021-07-17T21:08:05+00:00 1 Answers 3 views 0

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    2021-07-17T21:09:18+00:00

    Answer:

    559.5 N

    Explanation:

    Applying,

    v² = u²+2gs…………. Equation 1

    Where v = final velocity,

    From the question,

    Given: s = 5.10 m, u = 0 m/s ( from rest)

    Constant: 9.8 m/s²

    Therefore,

    v² = 0²+2×9.8×5.1

    v² = 99.96

    v = √(99.96)

    v = 9.99 m/s

    As the diver eneters the water,

    u = 9.99 m/s, v = 0 m/s

    Given: t = 1.34 s

    Apply

    a = (v-u)/t

    a = 9.99/1.34

    a = -7.46 m/s²

    F = ma………….. Equation 2

    Where F = force, m = mass

    Given: m = 75 kg, a = -7.46 m/s²,

    F = 75(-7.46)

    F = -559.5 N

    Hence the average force exerted on the diver is 559.5 N

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