A 72.0 kg ice skater is moving at 3.1 m/s on frictionless ice throws a 0.21 kg snowball horizontally at a speed of 28.0 m/s. What is the fin

Question

A 72.0 kg ice skater is moving at 3.1 m/s on frictionless ice throws a 0.21 kg snowball horizontally at a speed of 28.0 m/s. What is the final velocity of the skater?

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Neala 4 months 2021-09-02T13:33:32+00:00 1 Answers 0 views 0

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  1. thienthanh
    0
    2021-09-02T13:35:00+00:00
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    Answer:

    the final velocity of the skater after throwing the snowball is 3.17 m/s.

    Explanation:

    Given;

    mass of the ice skater, m₁ = 72 kg

    initial velocity of the ice skater, u₁ = 3.1 m/s

    mass of the snowball, m₂ = 0.21 kg

    initial speed of the snowball, u₂ = 28.0 m/s

    Let the final velocity of the skater after throwing the snowball = v

    Apply the principle of conservation of linear momentum to determine v;

    m₁u₁ + m₂u₂ = v(m₁ + m₂)

    72 x 3.1   +  0.21 x 28  = v(72 + 0.21)

    229.08 = v(72.21)

    v = 229.08 / 72.21

    v = 3.17 m/s

    Therefore, the final velocity of the skater after throwing the snowball is 3.17 m/s.

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