Share
A 72.0 kg ice skater is moving at 3.1 m/s on frictionless ice throws a 0.21 kg snowball horizontally at a speed of 28.0 m/s. What is the fin
Question
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Answers ( )
Answer:
the final velocity of the skater after throwing the snowball is 3.17 m/s.
Explanation:
Given;
mass of the ice skater, m₁ = 72 kg
initial velocity of the ice skater, u₁ = 3.1 m/s
mass of the snowball, m₂ = 0.21 kg
initial speed of the snowball, u₂ = 28.0 m/s
Let the final velocity of the skater after throwing the snowball = v
Apply the principle of conservation of linear momentum to determine v;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
72 x 3.1 + 0.21 x 28 = v(72 + 0.21)
229.08 = v(72.21)
v = 229.08 / 72.21
v = 3.17 m/s
Therefore, the final velocity of the skater after throwing the snowball is 3.17 m/s.