A 7-cm-external-diameter, 18-m-long hot-water pipe at 80°C is losing heat to the surrounding air at 5°C by natural convection with a heat tr

Question

A 7-cm-external-diameter, 18-m-long hot-water pipe at 80°C is losing heat to the surrounding air at 5°C by natural convection with a heat transfer coefficient of 25 W/m2·°C. Determine the rate of heat loss from the pipe by natural convection, in kW.

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Thiên Di 3 years 2021-08-27T11:54:12+00:00 1 Answers 2 views 0

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    2021-08-27T11:55:28+00:00

    Answer:

    Explanation:

    Given:

    D = 7 cm

    = 0.07 m

    A = pi × r ^2

    = pi × (0.07/2)^2

    = 0.00385 m2

    T1 = 80°C

    T2 = 5°C

    h = 25 W/m2·°C

    Q = A × h × delta T

    = 0.00385 × 25 × (80 – 5)

    = 7.22 W

    = 7.22 × 10^-3 kW.

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