A 65 kg bobsled is pushed along a horizontal surface by two athletes. After the bobsled is pushed a distance of 6.5 m starting from rest, it

Question

A 65 kg bobsled is pushed along a horizontal surface by two athletes. After the bobsled is pushed a distance of 6.5 m starting from rest, its speed is 7.0 m/s. Find the magnitude of the net force on the bobsled.

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Nick 3 weeks 2021-08-25T03:02:03+00:00 2 Answers 0 views 0

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    0
    2021-08-25T03:03:05+00:00

    Answer:

    245.05 N

    Explanation:

    From Newton’s law of fundamental equation,

    F = ma…………….. Equation 1

    Where F = Force, m = mass of the bobsled, a = acceleration,

    But

    v² = u²+2as……………….. Equation 2

    Where v and u = final and initial velocity respectively, s = distance.

    Given: v = 7 m/s, u = 0 m/s, s = 6.5 m

    Substitute into equation 2

    7² = 0²+2(6.5)(a)

    49 = 13a

    a = 49/13

    a = 3.77 m/s²

    Also Given: m = 65 kg,

    Substitute into equation 1

    F = 65(3.77)

    F = 245.05 N

    0
    2021-08-25T03:03:57+00:00

    Answer:

    245 N

    Explanation:

    Force is given by mass × acceleration. The mass is given and we need to determine the acceleration.

    The bobsled starts from rest; its initial velocity is 0.0 m/s. After a distance of 6.5 m, its speed is 7.0 m/s

    We use the equation of motion:

    v^2 = v_0^2 + 2as

    a = \dfrac{v^2-v_0^2}{2s}

    v is the final velocity, v_0 is the initial velocity, a is the acceleration and s is the distance.

    a = \dfrac{7.0^2-0.0^2}{2\times6.5} = \dfrac{49}{13}

    The net force is

    F = 65\times\dfrac{49}{13} = 245\text{ N}

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