A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.40 m, what is the

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A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.40 m, what is the average resistance force exerted on her by the water

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RI SƠ 2 weeks 2021-08-31T23:39:46+00:00 1 Answers 0 views 0

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    2021-08-31T23:40:59+00:00

    Answer:

    19372.29 N

    Explanation:

    Kinetic Energy of the man = Work done by the average resistive force of water.

    mg(H+d) = F×d………………………. Equation 1

    where, m = mass of the woman, H = Height of the platform, d = depth of water reached, F = average resistive force exerted by water.

    make F the subject of the equation,

    F = mg(H+d)/d…………………. Equation 2

    Given: m = 65.0 kg, H = 10 m, d = 3.4 m, g = 9.8 m/s²

    Substitute into equation 2

    F = 65(9.8)(100+3.4)/3.4

    F = 19372.29 N

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