A 630 W bulb and a 315 W bulb are both designed to operate at standard household voltage of 120 V. Determine which bulb has the lower filame

Question

A 630 W bulb and a 315 W bulb are both designed to operate at standard household voltage of 120 V. Determine which bulb has the lower filament resistance and then calculate the value of its resistance.

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Calantha 2 months 2021-08-21T23:09:45+00:00 1 Answers 0 views 0

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    2021-08-21T23:10:52+00:00

    Answer:

    630 W bulb has lower resistance than 315 W bulb

    Explanation:

    The resistance of the bulb can be found using the operating voltage of the bulbs and their wattage.

    As we know from Ohm’s law

    V = IR

    I = V/R

    Also power is given by

    P = VI

    P = V*(V/R)

    P = V²/R

    R = V²/P

    For Bulb 1:

    R = 120²/630

    R = 22.85 Ω

    For Bulb 2:

    R = 120²/315

    R = 45.71 Ω

    Therefore, the bulb with a higher wattage of 630 W has lower resistance than the bulb with a lower wattage of 315 W.

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