A 60-cm-long heating wire is connected to a 120 v outlet. the wire the total charge a household battery can supply is given in units of ma⋅h

Question

A 60-cm-long heating wire is connected to a 120 v outlet. the wire the total charge a household battery can supply is given in units of ma⋅h. for example, a 9.0 v alkaline battery is rated 450 ma⋅h, meaning that such a battery could supply a 1 ma current for 450 h, a 2 ma current for 225 h, etc.e dissipates 45 w.

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Nguyệt Ánh 6 months 2021-07-15T02:43:00+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-07-15T02:44:16+00:00

    Complete part of Question:

    How much energy in Joules is this battery capable of supplying?

    Answer:

    Energy = 14,580 J

    Explanation:

    NOTE: The question later focuses on the energy the battery can supply and not the 120 V outlet.

    The energy the battery is capable of supplying is given by the equation:

    Energy, E = IVt

    The voltage of the battery, V = 9.0 V

    The battery is rated 450 mAh = 0.45 Ah

    That is, It = 0.45 Ah = 0.45*3600 = 1620 A-sec

    Q = It = 1620 As

    Energy = 1620 * 9

    E = 14,580 J

    0
    2021-07-15T02:44:43+00:00

    Complete Question

    A 60-cm-long heating wire is connected to a 120 v outlet. the wire the total charge a household battery can supply is given in units of ma⋅h. for example, a 9.0 v alkaline battery is rated 450 ma⋅h, meaning that such a battery could supply a 1 ma current for 450 h, a 2 ma current for 225 h, etc.

    How much energy, in joules, is this battery capable of supplying?

    Answer:

    The amount of energy the battery is capable of supplying is E= 14580 J

    Explanation:

    From the question we are told that

           The 9.0V battery is rated 450 {\rm mA} \cdot {\rm hr}.

       Generally Power is mathematically represented as

                                Power = \frac{Energy}{time }

                                 P = \frac{E}{t}

    Making E the subject of the formula

                           E = P* t

       Power can also be represented mathematically as

                       P = I * V

    Where I is current and V is voltage

                 Therefore the formula for energy would be

                           E = I * V * t

     From the question we are told that

           Substituting 1 mA = 1*10^{-3} A  for I

                                 9 volt for V

                                 450 hr = 450 *3600 sec = 1620000 \ sec for t

                                  E = 1 *10^{-3} * 9 * 1620000

                                     E= 14580 J

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